Mutable and immutable useRef semantics with React & TypeScript

Wojciech Matuszewski - Jun 12 '21 - - Dev Community

In this post, you will learn how different ways declaring a ref with useRef hook influence the immutability of the current ref property. We will be looking at how to make the current property immutable, mutable, and know without much effort if the ref is one or the other.

All the behavior I'm going to talk about is only relevant in the context of TypeScript. The mutability / immutability is enforced at type level, not runtime level.

Immutable current property

The immutable semantics of the useRef hooks are usually used with DOM elements. A common use-case might be to get the ref of an element and focus that element whenever a button is clicked.

Here is how I would write that.

import * as React from "react";

const Component = () => {
  const inputRef = React.useRef<HTMLInputElement>(null);

  return (
    <div>
      <input type="text" name="name" ref={inputRef} />
      <button type="button" onClick={() => inputRef.current?.focus()}>
        Click to focus the input
      </button>
    </div>
  );
};
Enter fullscreen mode Exit fullscreen mode

Notice the type and the value I’ve initialized the useRef with. The semantics I’ve used signal that I’m relying on React to manage the ref for me. In our case, this means that I cannot mutate the inputRef.current. If I ever tried to do that, TypeScript would complain.

import * as React from "react";

const Component = () => {
  const inputRef = React.useRef<HTMLInputElement>(null);


  return (
    <div>
        {/* Cannot assign to 'current' because it is a read-only property */}
      <input type = "text" ref = {callbackRefValue => inputRef.current = callbackRefValue}>
      <button type="button" onClick={() => inputRef.current?.focus()}>
        Click to focus the input
      </button>
    </div>
  );
};
Enter fullscreen mode Exit fullscreen mode

After writing similar code for a while, I’ve created a rule of thumb I follow to understand if the ref that I’m looking is immutable.

If the useRef is initialized with null and the initial value does not belong to the provided type, the current property is immutable.

In our case, the null initial value does not belong to the type HTMLInputElement so the current property cannot be mutated.

Mutable current property

To have the current property of the ref be mutable, we need to change how we are declaring ref itself.

Suppose we are writing a component that deals with timers. The useRef hook is an ideal candidate to hold a reference to a timer. With the timer reference at hand, we can make sure that we clear the timer when the component unmounts.

Here is an, albeit a bit contrived, example.

import * as React from "react";

const Component = () => {
  const timerRef = React.useRef<number | null>(null);
  // This is also a valid declaration
  // const timerRef = React.useRef<number>()

    React.useEffect(() => {
        // Mutation of the `current` property
        timerRef.current = setTimeout(/* ... */)
        return clearInterval(timerRef.current)
    }, [])

  return (
      // ...
  );
};
Enter fullscreen mode Exit fullscreen mode

Since in the beginning, I have no way to know what the reference to the later declared setTimeout might be, I've initialized the useRef with null. Apart from the types, the declaration of the ref might seem eerily similar to the one in the Immutable current property section.
However, since the initially provided value (in our case null) wholly belongs to the type I've declared the useRef with (number | null), the current property is allowed to be mutable.

Similarly to the immutable current property case, here is my rule of thumb.

If the useRef is initialized with a value that belongs to the provided type, the current property of the ref is mutable.

In our case, the null initial value belongs to the type number | null so the current property can be mutated.
As an alternative, I could have declared the timerRef variable the following way

const timerRef = React.useRef<number>(); // the `timerRef.current` is also mutable
Enter fullscreen mode Exit fullscreen mode

Why is the current allowed to be mutated in this case? Because the timerRef is implicitly initialized with the undefined value. The undefined value belongs to the type I've declared the timerRef - the React.useRef typings are overloaded depending on the type of the initial value.

const timerRef = React.useRef<number>();

// Really is
const timerRef = React.useRef<number>(undefined);

// The `React.useRef` type definitions specify an overload whenever the type of the initial value is `undefined`
function useRef<T = undefined>(): MutableRefObject<T | undefined>; // Notice the `MutableRefObject`.
Enter fullscreen mode Exit fullscreen mode

Summary

When I started working with React & TypeScript, I found the difference between mutable and immutable refs quite confusing. I hope that this article was helpful and cleared some of the questions you might have had on the subject matter.

You can find me on twitter - @wm_matuszewski.

Thank you for your time.

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
Terabox Video Player